A body of mass 4m is split into two equal parts by an internal explosion which generates a kinetic energy E. If, after the explosion, the parts move in the same line as before, then what is their relative speed?

A body of mass M splits into two parts aM and (1-alpha) M by an internal explosion, which generates kinetic energy T. After explosion if the two parts move in the same direction as before, their relative speed will be -

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

A projectile is moving at 20 m s^(-1) at its highest point where it breaks into equal parts due to an internal explosion. Just after explosion, one part moves vertically up at 30 ms^(-1) with respect to the ground. Then the other part will move at :

A projectile is moving at 20 m s^(-1) at its highest point where it breaks into equal parts due to an internal explosion. Just after explosion, one part moves vertically up at 30 ms^(-1) with respect to the ground. Then the other part will move at :

A bomb of mass '5m' at rest explodes into three parts of masses 2m , 2m and m . After explosion, the equal parts move at right angles with speed v each. Find speed of the third part and total energy released during explosion.

A bomb of mass 5m at rest explodes into three parts of masses 2m , 2m and m . After explosion, the equal parts move at right angles with speed v each. Find speed of the third part and total energy released during explosion.

A particles has velocity 40 m/s is exploded into two equal parts one with 60 m/s in same direction. The ratio of kinetic energy of individual particles after explosion is K:4, Then K is