The maximum velocity of a harmonic oxcillator is `alpha` and its maximum acceleration is `beta`. Its time period will be :

The maximum velocity of a particle executing S.H.M is 0.08 mis. If its maximum acceleration is 0.32 m/ s^2 . Its period and and amplitude are given by

The maximum velocity of a particle executing SHM is v. If its amplitude of oscillation is doubled and its time period is made half of its initial value, the maximum velocity of it will be

A particle executes SHM such that, the maximum velocity during the oscillation is numerically equal to half the maximum acceleration. What is the time period?

The maximum speed of a particle executing SHM is 10 m/s and maximum acceleration is 31.4m//s^(2) . Its periodic time is

The maximum velocity of a particle executing SHM is 100cms^(-1) and the maximum acceleration is 157cms^(-2) determine the periodic time

The maximum acceleration of a simple harmonic oscillator is a_(0) and the maximum velocity is V_(0) . What is the displacement amplitude ?