If f : `RrarrR` is such that `f(3)=16,f'(3)=4,` then `underset(x rarr 3) lim(xf(3)-3f(x))/(x-3)=`

If f(2)=4,f'(2)=4, then value of underset(x rarr 2)lim(xf(2)-2f(x))/(x-2) is

If f(3)=6 and f'(3)=2, then lim_(x to 3) (xf (3)-3f(x))/(x-3) is given by

If f(3)=6andf'(3)=2 , find the value of lim_(xto3)(xf(3)-3f(x))/(x-3) .

If f(9)=9" and "f'(9)=4," then "underset(xto9)("lim")(sqrt(f(x))-3)/(sqrt(x)-3)=

Q.if f(3)=6 and f'(3)=2, then lim it_(x rarr3)(xf(3)-3f(x))/(x-3) is given by :(A)6 (b) 4(C)0(D)1

If f(9) =9, f^(')(9) = 4 , then lim_(x rarr 9)(sqrt(f(x))-3)/(sqrtx - 3) =

If f be a function such that f(9) = 9 and f'(9) = 3, then : lim_(x rarr 9) (sqrt(f(x)) - 3)/(sqrt(x) - 3) is :

If f(9)=9,f'(9)=4,then(lim)_(x rarr9)(sqrt(f(x))-3)/(sqrt(x)-3)=

If f(9)=9 , f'(9)= 4 then lim _ (x rarr9) (sqrt f(x) -3)/(sqrt(x)-3) =_____.