The time period and the amplitude of a simple pendulum are 4 seconds and 0.20 meter respectively. If the displacement is 0.1 meter at time t=0, the equation on its displacement is represented by :-

The amplitude and time period of a simple pendulum bob are 0.05m and 2 s respectively. Then the maximum velocity of the bob is :

The time period of a simple pendulum is 2 seconds. If its length is increased by 4 times, then its period becomes

A simple pendulum is described by a = -16x , where a is acceleration, x is displacement in meter. What is the time period ?

The periodic time of a simple pendulum of length 1 m and amplitude 2 cm is 5 seconds. If the amplitude is made 4 cm , its periodic time in seconds will be

The periodic time of a simple pendulum of length 1 m and amplitude 2 cm is 5 seconds. If the amplitude is made 4 cm , its periodic time in seconds will be

The amplitude and time period of a aprticle of mass 0.1kg executing simple harmonic motion are 1m and 6.28s , respectively. Then its angular frequency and acceleration at a displacement fo 0.5m are respectively

A body makes angular simple harmonic motion of amplitude pi/10rad and time period 0.5s. If the body is at a displacement theta=pi/10 rad at t=0, write the equation giving the angular displacement as a function of time.

A body makes angular simple harmonic motion of amplitude pi//10rad and time period 0.05s . If the body is at a displacement theta = pi//10 rad at t = 0 , write the equation giving angular displacement as a function of time.