Altitude AD of equilateral `DeltaABC` is a diameter of circle. If circle intersects AB and AC at E & F. respectively, as shown. Find ratio of EF:BC

Altitude AD of equilateral DeltaABC is a diameter of circle O. If the circle intersets AbarB and AC at E and F, respectively, find the ratio of EF : BC?

Altitude AD of an equilateral triangle ABC is a diameter of circle. If circle intersect AB and AC at E and F then (EF)/(BC) =

In the given figure, the perpendicular bisector AD of the equilateral triangle ABC is same as the diameter of the circle intersects the sides AB and AC at P and Q, respectively. If the height of the triangle be 10sqrt3 cm , find CQ.

In a Delta ABC, AD is a median. The bisectors of angle ADB and angle ADC meets AB & AC at E and F respectively . AE:BE=3:4 . Find EF:BC .

A circle is drown with diameter as the high of an equilateral triangles. As shown in the figure, the circle cuts side AB and AC at point P and Q. Find the ratio of AP : PB

In a DeltaABC , AD is a median . The bisectors of angleADBandangleADC meet AB and AC at E and F respectively . If the ratio of AE : BE = 2 : 3 , then find the ratio of EF : BC.

ABCD is a cyclic quadrilateral. A circle passing through A and B meets AD and BC in E and F respectively. Prove that EF||DC

In DeltaABC , E and F are the midpoints of sides AB and AC respectively. If EF=5cm, find BC.

AD is a median of triangleABC . The bisectors of angleADB and angleADC meets AB and AC in E and F respectively prove that EF||BC.

AD is a median of Delta ABC. The bisector of /_ADB and /_ADC meet AB and AC in E and F respectively.Prove that EF |BC