A galvanometer of resistance 98 ohms is shunted by a resistance of 2 ohms. The fraction of the total current that pass through is.

A galvanometer has a resistance of 98 Omega .it is shunted by 2Omega resistance. The fraction of the total current passing through the galvanometer is

A galvanometer of resistance 90 Omega is shunted by a resistance of 10 Omega . What fraction of main current passes through the shunt ?

A galvanometer of resistance 90 Omega is shunted by a resistance of 10 Omega . What fraction of main current passes through the shunt ?

A galvanomter of resistance 50Omega is shunted by a resistance of 5Omega . What fraction of the main current passes through the galvanometer? Through the shunt?

When a galvanometer of resistance G is shunted with a low resistance S, then the effective resistance R_(eff) of galvanometer becomes R_(eff)=(GS)/(G+S) If current is passed through such a galvanometer, then the major amount of current flows through shunt and the rest through galvanometer, i.e., the current divides itself in the inverse ratio of resistance. Read the above passage and answer the following questions: (i) Why is the resistance of shunted galvanometer lower than that of shunt? (ii) A galvanometer of resistance 30Omega is shunted by a resistance of 3Omega . What fraction of the main current passes (i) through the galvanometer and (ii) through the shunt? (iii) What are the basic values you learn from the above study?

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm. If the total current is 1 A, the part of it passing through the shunt will be

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm . If the total current is 1 amp , the part of it passing through the shunt will be

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm . If the total current is 1 amp , the part of it passing through the shunt will be

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm . If the total current is 1 amp , the part of it passing through the shunt will be

A galvanometer having a resistance of 18 Omega is shunted by a wire of resistance 2 Omega . If the total current to be passed is 2A, then the part of it passing through the shunt will be