`mx^(2) -bx +k = 0`
Find time after which of the energy will be come half of initial maximum value in damped forced oscillation .

Find the displacement of a simple harmonic oscillator at which its PE is half of the maximum energy of the oscillator.

Find the displacement of a simple harmonic oscillator at which its PE is half of the maximum energy of the oscillator.

Find the displacement of a simple harmonic oscillator at which its PE is half of the maximum energy of the oscillator.

Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator.

Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator.

Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator.

When an oscillator completes 50 oscillations its amplitude reduced to half of initial value (A_0) . The amplitude of oscillation, when it completes 150 oscillations is

Damped harmonic oscillator consists of a block (m=2kg) a spring (k=8 pi^(2)N/m) and a damping force (F=-bv) .Initially it oscillates with an amplitude of 25cm . Because of the damping the amplitude falls to three-fourth of this initial value at the completion of four oscillations.What is the value of b ? (Assume small damping and take : ln((3)/(4))=-0.28