If `f (x) =(1)/(x +1)` then its differentiate is given by :

If f(x) = x/(x+1) , then its differential is given by

Given f' (1) = 1 and d/(dx)f(2x)=f'(x) AA x > 0 . If f' (x) is differentiable then there exists a number c in (2,4) such that f'' (c) equals

Prove that the function f given by f(x) = |x-1|, x in R, x=1 is not differentiable at x = 1.

Given f'(1)=1 and (d)/(dx)f(2x))=f'(x)AA x>0 If f'(x) is differentiable then there exists a numberd x in(2,4) such that f''(c) equals

Given f'(1)=1 and (d)/(dx)(f(2x))=f'(x)AA x>0. If f'(x) is differentiable then there exies a number c in(2,4) such that f''(c) equals

Given f^(prime)(1)=1"and"d/(dx)(f(2x))=f^(prime)(x)AAx > 0 .If f^(prime)(x) is differentiable then there exies a number c in (2,4) such that f''(c) equals

Given f^(prime)(1)=1"and"d/(dx)(f(2x))=f^(prime)(x)AAx > 0 .If f^(prime)(x) is differentiable then there exies a number c in (2,4) such that f''(c) equals

The function f : R rarr R given by f(x) = - |x-1| is (a) continuous as well as differentiable at x = 1 (b) not continuous but differentiable at x = 1 (c) continous but not differentiable at x = 1 (d) neither continous nor differentiable at x = 1