Two waves represented by `y_1=10 sin (2000 pi t)` and `y_2=10 sin (2000 pi t + pi//2)` superposed at any point at a particular instant. The resultant amplitude is

Two waves represented by y_1 =a sin omega t and y_2 =a sin (omega t+phi) "with " phi =(pi)/2 are superposed at any point at a particular instant. The resultant amplitude is

Two waves are represented at a certain point by the equation y_1 = 10 sin 2000 pi t and y_2 = 10 sin [ 2000 pi t + (pi//2)] , for the resultant wave

Two waves represented as y_(1) = A_(1) sin omega t and y_(2) = A_(2) cos omega t superpose at a point in space. Find out the amplitude of the resultant wave at that point .

The waves produced by two sources of sound are given by y_(1) = 10 sin (200 pi t) and y_(2) = 10 sin (210 pi t) . If the waves superimpose, then the no. of beats heard by the listener in one minute will be