The time period of a particle executing `SHM` is `T`. After a time `T//6` after it passes its mean position, then at`t = 0` its :

Time period of a particle executing SHM is 16s.At time t = 2s , it crosses the mean position . Its amplitude of motion is ( 32sqrt(2))/(pi) m . Its velocity at t = 4s is

Time period of a particle executing SHM is 16s.At time t = 2s , it crosses the mean position . Its amplitude of motion is ( 32sqrt(2))/(pi) m . Its velocity at t = 4s is

The time period of a particle in simple harmonic motion is T. Assume potential energy at mean position to be zero. After a time of (T)/(6) it passes its mean position ,then at t=0 its,

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

The time period of a particle in simple harmonic motion is T. Assume potential energy at mean position to be zero. After a time of (T)/(6) it passes its mean position its,

The periodic time of a particle executing S.H.M. is12 second.After how much intervalfrom t=0 will its displacement be half of its amplitude ?

The periodic time of a particle executing S.H.M. is12 second.After how much intervalfrom t=0 will its displacement be half of its amplitude ?

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.