बहुपद `f(x)=3x^(4)-8x^(3)-x^(2)-5x-5` को `(x-3)` से भाग दीजिए।

If f(x)=7x^(4)-2x^(3)-8x-5 find f(-1)

Divide 3x^(4)-5x^(3)-2x^2-8x+3 by x^(2)+5x+3

f:R rarr R o* f(x)=x^(6)-3x^(5)+8x^(3)+5 Then f(x) is

Let f(x)=x^(8)-6x^(7)+5x^(6)+x^(4)-5x^(3)-x^(2)-3x+3AA x in R then f(5) is equal to :-

From the sum of 6x^(4) - 3x^(3) + 7x^(2) - 5x + 1 and -3x^(4) + 5x^(3) - 9x^(2) + 7x - 2 subtract 2x^(4) - 5x^(3) + 2x^(2) - 6x - 8

If f(x)=x^(3)-4x+8 , then f(5)=

f(x) = x^(2) -5x + 6 in [-3, 8]

Find f ' (x) if f(x)=2x^3-5x^2-4x+3 ,

Add : 3x^(2)+5x-4, 2x+3-x^(2) and 8-3x+7x^(2) .

Find the intervals in which the following function are increasing or decreasing. f(x)=10-6x-2x^2 f(x)=x^2+2x-5 f(x)=6-9x-x^2 f(x)=2x^3-12 x^2+18 x+15 f(x)=5+36 x+3x^2-2x^3 f(x)=8+36 x+3x^2-2x^3 f(x)=5x^3-15 x^2-120 x+3 f(x)=x^3-6x^2-36 x+2 f(x)=2x^3-15 x^2+36 x+1 f(x)=2x^3+9x^2+20 f(x)=2x^3-9x^2+12 x-5 f(x)=6+12 x+3x^2-2x^3 f(x)=2x^3-24 x+107 f(x)=-2x^3-9x^2-12 x+1 f(x)=(x-1)(x-2)^2 f(x)=x^3-12 x^2+36 x+17 f(x)=2x^3-24+7 f(x)=3/(10)x^4-4/5x^3-3x^2+(36)/5x+11 f(x)=x^4-4x f(x)=(x^4)/4+2/3x^3-5/2x^2-6x+7 f(x)=x^4-4x^3+4x^2+15 f(x)=5x^(3/2)-3x^(5/2),x >0 f(x)==x^8+6x^2 f(x)==x^3-6x^2+9x+15 f(x)={x(x-2)}^2 f(x)=3x^4-4x^3-12 x^2+5 f(x)=3/2x^4-4x^3-45 x^2+51 f(x)=log(2+x)-(2x)/(2+x),xR