[" In a YDSE with two identical slits,when the upper slits is covered with a thin,perfectly trans "],[" sheet of mica,the intensity at the centre of screen reduces to "75%" of the initial value.Second min "],[" observed to be above this point and third maxima below it.Which of the initial value.Second min "],[" value of phase difference caused by the mica sheet "],[[" (A) "(pi)/(3)," (C) "(17 pi)/(3)],[" The figure shows a transperes "," (C) "(17 pi)/(3)]]

In a YDSE with two identical slits, when the upper slit is covered with a thin, perfectly tranparent sheet of mica, the intensity at the centre of screen reduces ro 75% of the initial value second minima is observed to the above this point and third maxima below it which of the following can not be a possible value of phase difference caused by the mica sheet

In a YDSE with two identical slits, when the upper slit is covered with a thin, perfectly tranparent sheet of mica, the intensity at the centre of screen reduces ro 75% of the initial value. The second minima is observed to above this point and third maxima below it. which of the following can not be a possible value of phase difference caused by the mica sheet

In a YDSE with two identical slits, when the upper slit is covered with a thin, perfectly tranparent sheet of mica, the intensity at the centre of screen reduces ro 75% of the initial value. The second minima is observed to above this point and third maxima below it. which of the following can not be a possible value of phase difference caused by the mica sheet

In Young's experiment intensity at a point on the scrren is 75% of the maximum value. Minimum phase difference between the waves arriving at this point from the two slits will be

Minimum thickness of a mica sheet having mu=(3)/(2) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is

Minimum thickness of a mica sheet having mu=(3)/(2) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is

Minimum thickness of a mica sheet having mu=(3)/(2) which should be placed in front of one of the slits in YDSE is required to reduce the intensity at the centre of screen to half of maximum intensity is

In a regular YDSE, when thin film of refractive index mu is placed in front of the upper slit then it is observed that the intensity at the central point becomes half of the original intensity. It is also observed that the initial 3^(rd) maxima is now below the central point and the initial 4^(th) minima is above the central point. Now, a film of refractive index mu_(1) and thickness same as the above film. is put in the front of the lower slit also. It is observed that whole fringe pattern shifts by one fringe width. What is the value of mu_(1) ?

In young's double-slit experiment, both the slits produce equal intensities on a screen. A 100% transparent thin film of refractive index mu = 1.5 is kept in front of one of the slits, due to which the intensity at the point O on the screen becomes 75% of its initial value. If the wavelength of monochromatic light is 720 nm, then what is the minimum thickness (in nm) of the film?