Express `1/(1+cos2theta+isin2theta)` in the form of x + iy

Express 1/(1+cos theta-i sin theta) in the form of a +ib .

Express (1)/(1+cos theta-i sin theta) in the form of a+ib.

Express (1)/(1-cos theta+2i sin theta) in the form of a+ib .

Express (1)/(1-cos theta+2i sin theta) in the form x+iy.

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

(1)/(cos theta-isin theta) Find modulus

If (1 + cos theta - isin theta) ( 1+ cos 2 theta + isin 2 theta) = x +iy then x^(2) + y^(2) =

If (1 + cos theta + isin theta) (1 + cos 2 theta + isin 2theta) = x + iy then y =

If x + iy = (1)/(1-cos theta + 2 i sin theta), theta ne 2n pi, n in I , then maximum value of x is

The maximum value of the expression 1/(sin^2 theta + 3 sin theta cos theta + 5cos^2 theta) is