A body of mass M at rest is struck by a moving body of mass. Prove that the fraction of the initial kinetic energy of mass transferred to the struck body is `(4Mm)/((m+M)^(2))`

A body of mass M at rest is struck by a moving body of mass m.Prove that the fraction of the initial kinetic energy of mass transformed to the struck body is (4Mm)/((m+M)^2).

When a body of mass 'm' moves with a velocity 'v' its kinetic energy-

A body of mass m_1=4 kg moves at 5 hati m//s and another body of mass m_2=2 kg moves at 10 hati m//s . The kinetic energy of center of mass is

A body of mass ‘m’ is moving with velocity ‘v' .If the mass of the body is doubled what will be its kinetic energy?

A body of mass m is moving along x-axis with a velocity V, and another body of mass M is moving along y-axis with a velocity v. After collision they coalesce. (ii) Find the fraction of initial kinetic energy transferred to heat energy, after collision.