Home
Class 12
PHYSICS
A stone of mass 2kg whirled in a ho...

A stone of mass 2kg whirled in a horizontal circle attached at the end of 1.5 m long string. If the string makes an angle of ` 30 ^@ ` with vertical, compute its period ` ( g = 9.8 m//s ^ 2 ) ` .

Promotional Banner

Similar Questions

Explore conceptually related problems

A stone of mass 1 kg is whirled in horizontal circle attached at the end of a 1 m long string. If the string makes an angle of 30^@ with vertical, calculate the centripetal force acting on the stone. (g = 9.8 m/s^2)

A stone of mass 1 kg is whirled in horizontal circle attached at the end of a 1 m long string. If the string makes an angle of 30^(@) with vertical, calculate the centripetal force acting on the stone. (g=9.8" m"//"s"^(2)) .

A stone tied to a string of length l is whirled in a horizontal circle at a constant angular speed omega in a circle of radius r. If the string makes an angle theta with vertical then the tension in the string is :

A stone tied to a string of length l is whirled in a horizontal circle at a constant angular speed omega in a circle of radius r. If the string makes an angle theta with vertical then the tension in the string is :

A store of mass 1 kg , attached at the end of a 1 m long string is whirled in a horizontal circle . IF the string makes an angle of 30^@ with the vertical , then the approximate value of the centripetal force acting on the stone is (g=10m//s^2)

A ball of mass 0.12 kg is being whirled in a horizontal circle at the end of a string 0.5 m long. It is capable of making 231 revolutions in one minute. Find the breaking tension of the string