A wire of length 18m had been tied with electric pole at an angle of elevation `30^(@)` with the ground. As it is covering a long distance, it was cut and tied at an angle of elevation `60^(@)` with the ground. How much length of the wire was cut?

A wire of length 18 m had been tied with electric pole at an angle of elevation 30^(@) with the ground. Because it was covering a long distance, it was cut and tied at an angle of elevation 60^(@) with the ground. How much length of the wire was cut?

A wire of length 18 m had been tied with electric pole at an angle of elevation 30^(@) with the ground. Because it was covering a long distance, it was cut and tied at an angle of elevation 60^(@) with the ground. How much length of the wire was cut?

A wire of length 18 m had been tied with electric pole at an angle of elevation 30^(@) with the ground. Because it was covering a long distance, it was cut and tied at an angle of elevation 60^(@) with the ground. How much length of the wire was cut?

A wire of length 25 m had been tied with electric pole at an angle of elevation 30^@ with the ground. Because it was covering a long distance, it was cut and tied at an angle of elevation 60^@ with the ground how much length of the wire was cut.

The top of a 15m high tower make an angle of elevation of 60^(@) with the bottom of an electronic pole and angle of elevation of 30^(@) with the top of the pole. What is the height of the electric pole?

An electric pole 20m high stands up right on the ground with the help of steel wire to its top and affixed on the ground. If the steel wire makes 60^(@) with the horizontal ground, find the length of steel wire.

The angle of elevation of the top of a tower at a point G on the ground is 30^(@) . On walking 20 m towards the tower the angle of elevation becomes 60^(@) . The height of the tower is equal to :