A transverse wave along a string is given by
`y = 2 sin (2pi (3t - x) + (pi)/(4))`
where x and y are in cm and t in second. Find acceleration of a particle located at x = 4 cm at t = 1s.

The equation of a wave is y=4sin{(pi)/(2)(2t+(x)/(8))} where y,x are in cm and time in seconds . The acceleration of particle located at x=8cm and t=1sec is

A transverse wave travelling on a taut string is represented by: Y=0.01 sin 2 pi(10t-x) Y and x are in meters and t in seconds. Then,

A transverse wave travelling on a taut string is represented by: Y=0.01 sin 2 pi(10t-x) Y and x are in meters and t in seconds. Then,

The equation of a transverse wave is given by y=10 sin pi (0.01 x -2t ) where x and y are in cm and t is in second. Its frequency is

The equation of a transverse wave is given by y=10 sin pi (0.01 x -2t ) where x and y are in cm and t is in second. Its frequency is

A stationary wave is given by y = 5 sin (pi x)/(3) cos 40 pi t where x and y are in cm and t is in seconds What is the velocity of a particle of the string at the position x = 1.5 cm when t = 9/8 s

The equation of stationary wave along a stretched string is given by y = 5 sin(pi/3 x) cos 40pi t where x and y are in centimetre and t in second. The separation between two adjacent nodes is :