Consider the circel with centre at the point `(1,2)` and having the line `x =y` as a tangent. The area of the circel is

The equation of the circel with centre (2,1) and touchig the line 3x+4y=5 is-

The line 2x - y + 1 = 0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y = 4. The radius of the circle is :

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is :

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4 The radius of the circle is:

The centre of a circel is at (2, -3) and its circumference is 10pi, then the equation os the circel is-

The equation of the circel with cente at (1,-2) and passing through the centre of the given circle x ^(2) + y^(2) + 2y-3 =0, is

The equation of the circel with cente at (2,-2) and passing through the centre of the given circle x ^(2) + y^(2) + 2y-3 =0, is

In the adjoining figure, two tangents drawn from external point C to a circle with centre O touches the circel at the point P and Q respectively. A tangent drawn at another point R of the circle intersects CP and CQ at the points A and B respectively. If CP = 7 cm and BC =11 cm, then determine the length of BR.

Two tangents are draw from an external point A to the cirle with centre at O. If they touch the circel at the point B and C then prove that AO is the perpendicular bisector of BC.