Home
Class 12
MATHS
ABC is a triangle in which altitude BE a...

ABC is a triangle in which altitude BE and CF to sides AC and AB are equal. Show that
`Delta ABE ~= Delta ACF`
(ii) AB = AC, i.e., ABC is an isosceles triangle.

Promotional Banner

Similar Questions

Explore conceptually related problems

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see figure). Show that DeltaABE~=DeltaACF

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure) . Show that (i) DeltaABD ~= DeltaACE (ii) AB = AC i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal. Also DeltaABE ~= DeltaACF . Then triangle ABC is :

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal. Also DeltaABE ~= DeltaACF . Then triangle ABC is :

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig. 7.32). Show that (i) DeltaA B E~=DeltaA C F (ii) A B\ =\ A C , i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see Fig. 7.32). Show that (i) DeltaA B E~=DeltaA C F (ii) A B\ =\ A C , i.e., ABC is an isosceles triangle.

ABC is a triangle in which altitude BE and CF drawn on AC and AB respectively are equal. Prove that DeltaBEC~=DeltaCFB

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see figure). Show that AB=AC, i.e., ABC is an isosceles triangle.