Two soap bubbles of radii 1 mm and 2 mm merge isothermally . Then radius of the new bubble formed would be

Two soap bubbles of raddi 1mm and 2mm merge isothermally. Then radius of the new bubble formed would be

If a soap bubble of radius 3 cm coalesce with another soap bubble of radius 4 cm under isothermal conditions the radius of the redultant bubble formed is in cm

Prove that if two bubbles of radii r_(1) and r_(2) coalesce isothermally in vacuum then the radius of new bubble will be r=sqrt(r_(1)^(2)+r_(2)^(2))

Prove that if two bubbles of radii r_(1) and r_(2) coalesce isothermally in vacuum then the radius of new bubble will be r=sqrt(r_(1)^(2)+r_(2)^(2))

Prove that if two bubbles of radii r_(1) and r_(2) coalesce isothermally in vacuum then the radius of new bubble will be r=sqrt(r_(1)^(2)+r_(2)^(2))

Two soap bubbles of radius R_1 and R_2 combine isothermally to form a new soap bubble. Find radius of new soap bubble

Two liquid drops of radii 1 mm and 2 mm merge in vacuum isothermally. Radius of resulting drop is

Two soap bubble of radii 3 mm and 4 mm are in contact radius of curvature of interface between those two bubbles is