The atomic mass of a metal M is 56, then the empirical formulae of its oxide containing 70% metal

Assuming the atomic mass of a metal M to be 56, calculate the empirical formula of its oxide containing 70.0% M.

lf the equivalent mass of a metal (M) is x and the formula of its oxide is M_mO_n ,then show that the atomic mass of M is (2nx)/M

The atomic mass of a metal 'M' is 27 and its equivalent mass is 9. The formula of metal sulphate is _____.

0.72 gm of an oxide of a metal M on reduction with H_(2) gave 0.64 g of the metal . The atomic weight of the metal is 64 . The empirical formula of the compound is

An oxide of a metal (M) contains 40% by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is-

An oxide of metal M has 40% by mass of oxygen. Metal M has relative atomic mass of 24. The empirical formula of the oxide is:

Equivalent mass of metal M is E and the formula of its oxide is M_(x)O_(y) . Show that the valency and atomic mass of metal M are 2y/x and 2yE/x respectively.