A frustum of a uniform solid cone has base radius `R` and height `H` as shown. Radius of top surface is `(R )/(2)`. If height of centre of mass of frustum is `(11H)/(4n)` from base then n will be.

From a uniform solid cone of base radius R and height H, a symmetric cone of the base radius (R)/(2) is removed as shown. Then the centre of mass is shifted by H/n. Find the value of of n.

From a uniform solid cone of base radius R and height H, a symmetric cone of the base radius (R)/(2) is removed as shown. Then the centre of mass is shifted by H/n. Find the value of of n.

From a hemisphere of radius R a cone of base radius R/w and height R is cut as shown in figure. Find the height of centre of mass of the remaining object.

The total surface area of a cylinder of base radius r and height h is :

Find the volume of a right-circular cone of base radius r and height h.

The radius of base of a cone is r and height is h. Find its volume.

The radius of base of a cone is r and height is h. Find its volume.

The total surface area of a cylinder of base radius r and height h is______.

A uniform solid hemisphere of radius r is joined to a uniform solid right circular cone of base radius r and height sqrt3r . If both have same density, then find the position of centre of mass from centre of hemisphere