A metallic sphere cools from `50^(@)C` to `40^(@)C` in `300` seconds. If the room temperature is `20^(@)C` then its temperature in next `5` minutes will be -

A body cools from 70^(@)C to 50^(@)C in 5 minutes. Temperature of surroundings is 20^(@)C . Its temperature after next 10 minutes is

A body cools from 70^(@)C to 50^(@)C in 5minutes Temperature of surroundings is 20^(@)C Its temperature after next 10 minutes is .

The temperature of a body falls from 50^(@)C to 40^(@)C in 10 minutes. If the temperature of the surroundings is 20^(@)C Then temperature of the body after another 10 minutes will be

The temperature of a body falls from 50^(@)C to 40^(@)C in 10 minutes. If the temperature of the surroundings is 20^(@)C Then temperature of the body after another 10 minutes will be

A body cools from 71^(@) C. to 50^(@) C in 5 minutes. Temperature of surroundings is 20^(@) C. Its temperature after next 10 minutes is

A body cools from 50^@C to 40^@C in 5 mintues in surrounding temperature 20^@C . Find temperature of body in next 5 mintues.

A body cools from 50^@C to 40^@C in 5 mintues in surrounding temperature 20^@C . Find temperature of body in next 5 mintues.

A body cools from "60 ∘ C to 50 ∘C in 10 minutes.If the room temperature is "25 ∘ C then the temperature of the body at the end of the next "10" minutes will be

A body cools from 50^(@)C to 40^(@)C in 5 minutes. The surrounding temperature is 20^(@)C . What will be its temperature 5 minutes after reading 40^(@)C ? Use approximate method.

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be