At `5xx10^(4)` bar pressure density of diamond and graphite are `3 g//c c` and `2g//c c` respectively, at certain temperature `'T'`.Find the value of `DeltaU-DeltaH` for the conversion of 1 mole of graphite to 1 mole of diamond at temperature `'T' :`

At 5xx10^(5) bar pressure, density of diamond and graphite are 3 g//c c and 2g//c c respectively, at certain temperature T. (1 L. atm=100 J)

At 5xx10^(5) bar pressure, density of diamond and graphite are 3 g//c c and 2g//c c respectively, at certain temperature T. (1 L. atm=100 J)

At 500 kbar pressure density of diamond and graphite are 3 "g"//"cc" and 2 "g"//"cc" respectively, at certain temperature T. Find the value of |DeltaH-DeltaU| ("in kJ"//"mole") for the conversion of 1 mole of graphite 1 mole of diamond at 500 kbar pressure. (Given : 1 "bar" = 10^(5) "N"//"m"^(2))

Densities of diamond and graphite are 3 and 2 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1) , respectively. The increase of pressure on the equilibrium C_("diamond") hArr C_("graphite")

DeltaH_f^@ values (in kJ mol^(-1) ) for graphite , diamond and C_60 are respectively

Densities of diamond and graphite are 3.5 and 2.5 gm/ml. C_("daimond") hArr C_("graphite") , Delta_(t) H = -1.9 KJ/ mole favourable conditions for formation of diamond are