An electron (mass m) with an initial velocity `v=v_(0)hat(i)(v_(0)gt0)` is in an electric field `E=-E_(0)hat(l)(E_(0)="constant"gt0)`. Its de-Broglie wavelength at time t is given by

An electron mass m with an initial velocity vecv=v_0hati (v_0>0) is in an electric field vecE=-E_0hati(E_0=constant>0) . Its de-Broglie wavelength at time t is given by

An electron (mass m) with an initial velocity vecv=v_(0)hati is in an electric field vecE=E_(0)hatj . If lambda_(0)=h//mv_(0) . It's de-broglie wavelength at time t is given by

An electron (mass m) with an initial velocity vecv=v_(0)hati is in an electric field vecE=E_(0)hatj . If lambda_(0)h//mv_(0) . It's de-broglie wavelength at time t is given by

An electron (mass m)with an initial velocity vecv=v_(0)hati is in an electric field vecE=E_(0)hatj . If l,ambda_(0)=h..mv_(0) .it's de-Broglie wavelength at time t is given by

An electron (mass m) with an initial velocity vec(V) = v_(0) hat(i) is in an electric field vec(E) = E_(0) hat(j) . If lamda_(0) = (h)/(mv_(0)) , its de Broglie wavelength at time t is given by

Electron of mass m and intial velocity vecV=v_(0)hati (V_(0)gt0) enter electric field vecE=-E_(0)hati(E_(0)) constant at t=0 initial de-Broglie wavelength of electron is lambda_(0) then at time t=t its de-Broglie wavelength will be…..

An electron of mass m with an initial velocity vec(v) = v_(0) hat (i) (v_(0) gt 0) enters an electric field vec(E ) =- E_(0) hat (j) (E_(0) = constant gt 0) at t = 0 . If lambda_(0) is its de - Broglie wavelength initially, then its de - Broglie wavelength at time t is