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In a normal spinel types structure, the ...

In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by `Zn^(2+)` ions and `50%` of octahedral holes are occupied by `Fe^(3+)` ions. The formula of the compound is -

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In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is:

In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is:

In the spinel structur, oxides ions are cubical-closet packed whereas 1/8th of tetrahedral voids are occupied by A^(2+) cation and 1/2 of octahedral voids are occupied by B^(+) cations. The general formula of the compound having spinel structure is:

In the spinel structure, oxides ions are cubical - closest packed whereas 1//8 th of tetrahedral voids are occupied by A^(2+) cation and 1//2 of octahedral voids are occupied by B^(2+) cations. The general formula of the compound having spinel structure is :

In spinel structure, O^(2-) ions are cubic-close packed, where 1/8th of the tetrahedral holes are occupied by A^(2+) cations and 1/2 of the octahedral holes are occupied by cations B^(3+) . The general formula of this compound is

In spinel structure, O^(2-) ions are cubic-closed packed, wherease 1/8th of the tetrahedral holes are occupied by A^(2+) cations and 1/2 of the octahedral holes are occupied by cations B^(3+) . The general formula of this compound is