The angle of dip at a place is `37^(@)` and the vertical component of the earth's magnetic field is `6xx10^(-5) T`. What is the earth's magnetic field at this place?
`(tan 37^(@)=3/4)`

The angle of dip at a place is 37^(@) and the vertical component of the earth's magnetic field is 1.6xx 10^(-5)T. The earth's magnetic field at this place is (tan 37^@=3/4)

The angle of dip at a place is 37^(@) and the vertical component of the earth's magnetic field is 1.6xx 10^(-5)T. The earth's magnetic field at this place is (tan 37^@=3/4)

The angle of dip at a place is 40.6^(@) and the intensity of the vertical component of the earth's magnetic field V=6xx10^(-5) Tesla. The total intensity of the earth's magnetic field (I) at this place is

The angle of dip at a place is 40.6^(@) and the intensity of the vertical component of the earth's magnetic field V=6xx10^(-5) Tesla. The total intensity of the earth's magnetic field (I) at this place is

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

Angle of dip at a place is 30^(@) . If the vertical component of earth's magnetic field at that point is 7.5 xx 10^(-5) T, then the total magnetic field of earth at the point will be .

If the horizontal component of earth's magnetic field at this place is 3 xx 10^(-5) T, calculate the earth's total magnetic field at that place. Angle of dip = delta= 60^(@)