A source `S_(1)` is producing `10^(15)` photons per second of wavelength `5000Ã…`. Another source `S_(2)` is producing `1.02xx10^(15)`
Then, `("Power of" S_(2))//("Power of"S_(1))` is equal to

A source S_(1) is producing 10^(15) photons per second of wavelength 5000Ã… . Another source S_(2) is producing 1.02xx10^(15) wavelength 5100 A Then, ("Power of" S_(2))//("Power of"S_(1)) is equal to

A source S_(1) is producing 10^(15) photons//s of wavelength 5000 Å Another source S_(2) is producing 1.02 xx 10^(15) photons per second of wavelength 5100 Å . Then ("power of" S_(2))//("power of" S_(1)) is equal to

A source S_1 is producing 10^15 photons per second of wavelength 5000overset@A .Another source S_2 is producing 1.02 xx 10^15 , photon per second of wavelength 5100 overset@A . Then (power of S_2 ) (power of S_1 )is equal to:

A source S_(1) produces 10^(15) photon every second having wavelength of 5000Å .Another source S_(2) produce 1.02xx10^(15) photon every second with wavelength 5100 Å product [Power of S_(1) ] xx [Power of S_(2) ]=….

A light source of wavelength 520nm emits 1.04 xx 10^(15) photons per second while the second source of 460nm produces 1.38 xx 10^(15) photons per second. Then the ratio of power of second source to that of first source is

A light source of wavelength 520 nm emits 1.04 xx 10^(15) photons per second while the second source of 460 nm produces 1.38 xx 10^(15) photons per second. Then the ratio of power of second source to that of first source is………………

If a source of power 4 kW produces 10^(20) photons per second,the radiatoin belongs to a part of the spectrum called