`a+b=8,c-d=6,a+c=13,b+d=8` then `a,b,c,d`is :

a+b=8,c-d=6,a+c=13,b+d=8 then a,b,c,dis:

If a/4=b/5=c/6=d/8 then a:b:c:d is

If a,b,c and d satisfy the equation a+7b+3c+5d=0,8a+4b+6c+2d=-162a+6b+4c+8d=16,5a+3b+7c+d=-16 then (a+d)(b+c) equation

Solve for a, b, c and d when {:((b+c,c+a),(7-d,6-c))={:((9-d,8-d),(a+b,a+b)):}

If a, b, c, d satisfy the equation a + 7b + 3c + 5d = 0 , 8a + 4b + 6c + 2d = - 16 , 2a + 6b + 4c + 8d =16 and 5a + 3b + 7c + d = -16 then the value of (a + d) (b + c) =______

If A=[[a, b],[ c ,d]] , then a d j\ A is (a) [[-d,-b],[-c, a]] (b) [[d,-b],[-c ,a]] (c) [[d, b],[ c, a]] (d) [[d, c],[ b ,a]]

If A=[[a, b],[ c ,d]] , then a d j\ A is [[-d,-b],[-c, a]] (b) [[d,-b],[-c ,a]] (c) [[d, b],[ c, a]] (d) [[d, c],[ b ,a]]

If (a + b + c + d) (a - b - c + d) = (a + b - c - d) (a - b + c - d) , then prove that a : b = c : d

On the number line, points A, B,C are such that d(A, C) =10, d(C, B) =8, find the d(A,B) considering all possibilities.