The two tangents to the curve `ax^(2)+2h x y+by^(2) = 1, a gt 0` at the points where it crosses x-axis, are

The equation of the tangent to the curve y= be^(-(x)/(a)) at the point where it crosses the y-axis is-

Find the slope pf the tangents to the curve y = x^2 (x + 3) at the points where it crosses the X-axis

Find the slope of the tangents to the curve y=x^2(x+3) at the points where it crosses the x-axis.

The equation to the tangent to the curve y = be ^(-x/a) at the point where it crosses the y-axis is

Find the equation of tangents to the curve y = (x^(3) - 1) (x - 2) at the points, where the curve cuts the X-axis.

The equation of the tangent to the curve y=be^(-x/a) at the point where it crosses the y-axis is a)(x)/(a)-(y)/(b)=1( b) ax+by=1 c)ax -by=1( d) (x)/(a)+(y)/(b)=1

Write the equation of the tangent to the curve y=x^2-x+2 at the point where it crosses the y-axis.