e^(mx)

If lim_(x to 0) (1)/(x^(2)) (e^(2mx) = e^(x) - x) = (3)/(2) then the value of m is _____

If lim_(x to 0) (1)/(x^(2)) (e^(2mx) - e^(x) - x) = (3)/(2) then the value of m is _____

Show that y=e^(-x)+mx+n is a solution of the differential equation e^(x)(d^(2)y)/(dx^(2))-1=0.

The differential equation of y= e^(2x) (A cos mx +B sin mx) is

Given the cell reactions MX_((s))+e^(-)rarrM_((s))+X_((aq))^(-),E^(@)=0.207V and M_((aq))^(+)+e^(-)rarrM_((s)),E^(@)=0.799V The solubility of MX_((s)) at 298K is

If x^(mx^(mx^(mx..."to"oo)))=y^(ny^(ny^(ny..."to"oo)))," then "(dy)/(dx)=

If y = mx + 2 is parallel to a tangent to curve e^(4y) =1 + 16x^(2) then

Integrate the following with respect to 'x' a "sec"^(2) (bx + c) + q/(e^(l - mx)] dx .

The product of the roots of the equation x^(2) - 4 mx + 3e^(2 " log m") - 4 = 0 , then its roots will be real when m equals :

For a differentiable positive function f(x), if f(x)-etan ' x ? X E R and y-mx +c is a tangent to f(x) at (x1.yi) where x,e(?'?), then-