[" When a resistance of "2" ohm is connected across the terminals of a cell,the current is "0.5" amp.When the "],[" resistance is increased to "5" ohm,the current is "0.25" amp.The emf of the cell is :- "]

When a resistance of 2 ohm is connected across terminals of a cell, the current is 0.5 A . When the resistance is increased to 5 ohm, the current is 0.25 A The e.m.f. of the cell is

When a resistance of 2 ohm is connected across terminals of a cell, the current is 0.5 A . When the resistance is increased to 5 ohm, the current is 0.25 A The e.m.f. of the cell is

When a resistance of 2 ohm is connected across terminals of a cell, the current is 0.5 A . When the resistance is increased to 5 ohm, the current is 0.25 A The e.m.f. of the cell is

When a resistance of 2 Omega is connected across the terminals of a cell, the current is 0.5 A. When resistance is increased to 5 Omega , the current is 0.25 A. the emf of the cell is

When a resistance of 2 Ohm is connected across the terminals of a cell, the current is 0.5 A. If a resistance of 5 Ohm is connected across the cell then the current is 0.25 At the emf of the cell is:

When a resistance of 2 ohm is placed across a battery the current is 1 A and when the resistance across the terminals is 17 ohm, the current is 0.25A. The emf of the battery is

The current flowing through an external resistance of 2 Omega is 0.5 A when it is connected to the terminals of a cell. This current reduces to 0.25 A when the external resistance is 5 Omega .Use Kirchhoff's laws to find e.m.f. of cell

A Cell sends a current of 0.5 A through a 2 Omega resistance. If the resistance is increased by 5 Omega , the current falls to 0.25 A. Find the emf of the cell and its internal resistance.