k_(34):k_(35)*<1" ,then :- "

k_(35^(@))/k_(34^(@)) gt 1 , this means that:

If [{:(1,5),(3,4):}] [{:(3,1),(3,5):}] = [{:(18,26),(k,23):}] , then the value of k is

If [(1,2),(3,4)][(3,1),(2,5)]=[(7,11),(k ,23)] , then find the value of k.

If {:((1,2),(3,4)),((3,1),(2,5)),= ((7,11),(k,23)) , then write the value of 'k'

If the matrix [{:(-1,1,1),(3,k,4),(2,-3,5):}] has an inverse then the value of k.

Let quad cos(2k(pi)/(10))+i sin(2k(pi)/(10));k=1,2,34,...,9z_(k)=cos(2k(pi)/(10))+i sin(2k(pi)/(10));k=1,2,34,...,9 (A) For each z_(k) there exists a z_(j) such that z_(k).z_(j)=1 (ii) there exists a k in{1,2,3,...,9} such that z_(1)z=z_(k)

Find the value of k, if the area of the triangle formed by the points (k,0),(3,4) and (5,-2) is 10.

Find the value of k, if the area of the triangle formed by the points (k,0),(3,4) and (5,-2) is 10.

The number of ordered pairs (r, k) for which 6(""^(35)C_(r))=(k^(2)-3)(""^(36)C_(r+1)) , where k is an integer, is: