`int(dx)/(sinx+secx)`

Evaluate: int(dx)/(1-secx)

inte^(tanx)(sinx-secx)dx is equal to

inte^(tanx)(sinx-secx)dx is equal to

int(secx)/(sinx+cosx)dx=

inte^(tanx)(sinx-secx)dx , is equal to a) e^(tanx)*cosx+C b) e^(tanx)*sinx+C c) -e^(tanx)*cosx+C d) e^(tanx)*secx+C

inte^(sinx)((sinx+1)/(secx))dx is equal to

inte^(sinx)((sinx+1)/(secx))dx

inte^(sinx)((sinx+1)/(secx))dx is equal to

int(x+tanx)/(x.sinx.secx)dx=