In young double slit experiment, the intensity at a point where path difference is `lamda/6` is l. IF `l_0` denotes the maximum intensity `l/l_0`.

In Young's double slit experiment,the intensity at a point where the path difference is

In Young's double slit experiment, the intensity on the screen at a point where path difference is lambda is K. What will be the intensity at the point where path difference is lambda//4 ?

In Young's double slit experiment, the intensity on the screen at a point where path difference is lambda is K. What will be the intensity at the point where path difference is lambda//4 ?

The wavelength of the light used in Young’s double slit experiment is lambda . The intensity at a point on the screen where the path difference is lambda/6 is I. If I_0 denotes the maximum intensity, then the ratio of I and I_0 is..........

In a Young's double slit experiment, the intensity at a point where the path difference is (lamda)/6 ( lamda - wavelength of the light) is 1. If I_(0) denotes the maximum intensity, then I/(I_(0)) is equal to

The wavelength of the light used in Young’s double slit experiment, is lambda . The intensity at a point on the screen where the path difference is lambda/6 is I . If I_0 denotes the maximum intensity, then the ratio of I and I_0 is................

In Young's double slit experiment, the intensity at a point where the path difference is lamda/6 ( lamda is the wavelength of light) is I. if I_(0) denotes the maximum intensities, then I//I_(0) is equal to

In Young's double slit experiment, the intensity on the screen at a pont where path difference lamda is K. what will be the intensity at the point where the path difference is lamda/4 ?

The wavelength of the light used in Young's double slit experiment is lamda . The intensity at a point on the screen where the path difference is (lamda)/(6) is I . I_(0) mdenotes the maximum intensity then the ration of I and I_(0) is