2x-27<15-7x<=1

Factorise : x^(2)+6x-27

The roots of x^3 - 13x^2 +39 x-27=0 are in

The roots of x^3 - 13x^2 +39 x-27=0 are in

Evaluate : lim_(x to 9)(x^(3/2)-27)/(x-9)

If the value of a cuboid is 3x^(2)-27, then its possible dimensions are (a)3,x^(2),-27x(b)3,x-3,x+3(c)3,x^(2),27x(d)3,3,3

If x^(2)+6x-27>0;-x^(2)+3x+4>0 then x lies in the interval

If x^(2)+6x-27 gt 0 and x^(2)-3x-4 lt 0 , then :