A continuous function `f(x)onRvec` satisfies the relation `f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAAx ,y in RdotT h e nfin df(x)dot`

A continuous function f(x)onRvec satisfies the relation f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAA x ,y in RdotT h e n findf(x)dot

A continuous function f(x)onR->R satisfies the relation f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAAx ,y in R Then find f(x)dot

A continuous function f(x)onR->R satisfies the relation f(x)+f(2x+y)+5x y=f(3x-y)+2x^2+1forAAx ,y in R Then find f(x)dot

A continuous function f(x) on R rarr satisfies the relation f(x)+f(2x+y)+5xy=f(3x-y)+2x^(2)+1 for AA x,y in R. Then find f(x)

A continuous function f:RRrarrRR satisfies relation f(x)+f(2x+y)+5xy=f(3x-y)+2x^(2)+1" for all "x,y in RR, then the value of |f(4)| is equal to -

If f(x) satisfies the relation f(x+ y) = f ( x) + f( y ) for all x, y in R and f(1) = 5 then

A real valued function satisfies the relation f(x+y)=f(x)+f(y)+(e^x-1)(e^y-1) , AAx,y in R . If f'(0) = 2, find f(x).

If the function / satisfies the relation f(x+y)+f(x-y)=2f(x),f(y)AAx , y in R and f(0)!=0 , then

Suppose the function f(x) satisfies the relation f(x+y^3)=f(x)+f(y^3)dotAAx ,y in R and is differentiable for all xdot Statement 1: If f^(prime)(2)=a ,t h e nf^(prime)(-2)=a Statement 2: f(x) is an odd function.