[" 25.If "z=(1)/(1-cos theta-i sin theta)," then "Re(z)=],[[" (a) "0," (b) "(1)/(2)," (c) "cot(theta)/(2)]]

If z=(1)/(1-cos theta- isintheta) then Re(z)=....

If z = (1)/(1 - cos theta - i sin theta), the Re (z)=

If z = 1 - cos theta + i sin theta , then |z| =

If z=(1)/(1-cos theta-i sin theta), then Re(z) is a.0 b.(1)/(2) c.cot((theta)/(2)) d.(1)/(2)cot((theta)/(2))

If z=1/(1-cos theta-i sin theta), then Re(z) is a. 0 b. 1/2 c. cot(theta/2) d. 1/2 cot (theta/2)

z=i+sqrt(3)=r(cos theta+sin theta)

If a=cos theta+i sin theta then (1+a)/(1-a)=

If z= (cos theta, sin theta) , find (z-(1)/(z))

If z = (cos theta, sin theta) , find (z - 1/z)

If z= re^(i theta)" then "|e^(iz)|=