x और y के लिये हल कीजिए :
`(1)/(16x) +(1)/(15y) = (9)/(20)`
`(1)/(20x) -(1)/(27y) = (4)/(45)`

(1)/(2) + (1)/(4) + (1)/(8) + (1)/(16) + ….. = x , (1)/(3) + (1)/(9) + (1)/(27) + (1)/(81) + … = y, then

Find the centre and radius of each of the following circles : (i) (x - 3)^(2) + (y- 1) ^(2) = 9 (ii) (x - (1)/(2) ) ^(2) + ( y + (1)/(3) ) ^(2) = (1)/(16) (iii) (x + 5) ^(2) + ( y- 3 ) ^(2) = 20 (iv) x ^(2) + (y- 1 ) ^(2) = 2

If y = sin^(-1) (19/20x) + cos^(-1)(19/20x) , then (dy)/(dx)=

If y = sin^(-1) (19/20x) + cos^(-1)(19/20x) , then (dy)/(dx)=

Simplify (x+4)/(3x+4y) xx (9x^(2) - 16y^(2))/(2x^(2) +3x-20)

If A=[{:(2,3,10),(4,-6,5),(6,9,-20):}] , find A^(-1) . Using A^(-1) , solve the system of equations : {:((2)/(x)+(3)/(y)+(10)/(z)=2),((4)/(x)-(6)/(y)+(5)/(z)=5),((6)/(x)+(9)/(y)-(20)/(z)=-4):}

x+y+z = 15 if 9, x,y,z,a are in A.P., while (1)/( x) + ( 1)/( y) + ( 1)/( z) = ( 5)?( 3) if 9, x,y,z,a are in H.P., then the value of a will be :