[" 4.is projected vertically upwards with a velocity "10m/s" .Find the maximum "],[" teached by the body? "(g=10m/s^(2))]

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. (g=9.8m//s^(2))

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.(g=9.8 m/s^2)

A body is projected vertically upward with the velocity v=3hati+4hatjms^(-1) . The maximum height attained by the body is ( g=10ms^(-2) ).

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

A body is projected vertically upwards with a velocity of 10m//s . It reaches the maximum vertical height in time t. What will be the height covered in time t/2 ?

A body is rpojected vertically upwards with a velocity of 10m//s . If reaches the maximum height (h) in time (t). In time t//2 the height covered is (g= 10 m//s^@)