Beats are produced when two sound waves given by `y_(1) = A sin 200 pi t and y_(2) = A sin 210 pi t` are sounded together. How many beats are produced/sec?

Beats are produced by two waves given by y_(1)= a sin 2000 pi t and y_(2) =a sin 2008 pi t . The number of beats heard per second is

Two sound waves are given by y_(1) = A sin (1000 pit) and y_(2) = A sin (1008 pi t) . The number of beast heard per second is

Beats are produced by two waves y_(1) = a sin 2000 pi t and y_(2) = a sin 2008 pi t The number of beats heard per second is

When two waves y_(1) A sin 2000 pi t and y_(2) = A sin 2008 pi t are superposed, the number of beats produced per second is

Beats are produced by two waves given by y_1 = a sin2000 pit and y_2 =asin2008 pit . The number of beats heard per second is

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

Determine the resultant of two waves given by y_(1) = 4 sin(200 pi t) and y_(2) = 3 sin(200 pi t + pi//2) .

The waves produced by two sources of sound are given by y_(1) = 10 sin (200 pi t) and y_(2) = 10 sin (210 pi t) . If the waves superimpose, then the no. of beats heard by the listener in one minute will be