Home
Class 11
PHYSICS
[" In the circuit shown below "E(1)=E(2)...

[" In the circuit shown below "E_(1)=E_(2)=E_(3)=2" volts and "R_(1)],[=R_(2)=4Omega." The current flowing between points "A'" and "],['B'" through battery "E_(2)" is "]

Promotional Banner

Similar Questions

Explore conceptually related problems

In the circuit shown here, E_(1) = E_(2) = E_(3) = 2 V and R_(1) = R_(2) = 4 ohms . The current flowing between point A and B through battery E_(2) is

In the circuit shown here, E_(1) = E_(2) = E_(3) = 2 V and R_(1) = R_(2) = 4 ohms . The current flowing between point A and B through battery E_(2) is

In the circuit shown here, E_(1) = E_(2) = E_(3) = 2 V and R_(1) = R_(2) = 4 ohms . The current flowing between point A and B through battery E_(2) is

In the circuit shown in fig. 5.265, E_1 = E_2 = E_3 = 2V and R_1 = R_2 = 4Omega. The current flowing between points A and B through battery E_2 is

In the circuit shown in fig. 5.265, E_1 = E_2 = E_3 = 2V and R_1 = R_2 = 4Omega. The current flowing between points A and B through battery E_2 is

In the following circuit E_(1)=E_(2)=E_(3) 2V and R_(1)=R_(2)=AOmega . The current passing through battery E_(2) between points A and B is

In the circuit as shown in figure, E_(1)=2V , E_(2)=2V, E_(3)=1V, and R=r_(1)=r_(2)=r_(3)Omega . The potential difference between points A and B will be

In the circuit shown below E_(1) = 4.0 V, R_(1) = 2 Omega, E_(2) = 6.0 V, R_(2) = 4 Omega and R_(3) = 2 Omega . The current I_(1) is