" 2.Solve "(e^(x)+1)ydy+(y+1)dx=0

Solve dy/dx=(e^x+1)y.

The solution of the equation (e^x+1)ydy+(y+1)dx=0 , is (A) e^(x+y)=C(y+1)e^x (B) e^(x+y)=C(x+1)(y+1) (C) e^(x+y)=C(y+1)(1+e^x) (D) e^(xy)=C(x+y)(e^x+1)

Solve (1-x)dy=e^y dx

Solve (1-x)dy=e^y dx

Solve e^(-x+y)(dy)/(dx)=1

If the curve satisfy the equation (e^(x)+1)ydy=(y+1)e^(x)dx, passes through (0,0) and (k,1) then k is

The general solution of differential equation (e^(x)+1)ydy=(y+1)e^(x)dx is

The general solution of differential equation (e^(x)+1)ydy=(y+1)(e^(x))dx"is"