9AD^(2)=7AB^(2)" ."

In an equilateral triangle ABC , D is a point on side BC such that BD = 1/3 BC . Prove that 9 AD^(2)=7AB^(2) .

In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC . Prove that 9 AD^(2) = 7 AB^(2) .

In an equilateral triangle ABC, D is a point on side BC such that BD = (1)/(3) BC. Prove that 9 AD^(2) = 7 AB^(2) .

In an equilateral triangle ABC, D is a point on side BC such that BD = (1)/(3) BC. Prove that 9 AD^(2) = 7 AB^(2) .

The perimeters of two similar triangles are 25cm and 15cm respectively. If one side of the first triangle is 9cm, find the length of the corresponding side of the second triangle. OR In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9 AD^(2)=7AB^(2)

Solve the following sub question : In an equilateral triangle ABC, the side BC is trisected at D. prove that 9 AD^(2) = 7 AB^(2)

In an equilateral triangle ABC, if AD perp BC, then 2AB^(2)=3AD^(2)( b) 4AB^(2)=3AD^(2) (c) 3AB^(2)=4AD^(2)( d ) 3AB^(2)=2AD^(2)

In an equilateral triangle ABC if AD(perp)/(BC) , then 5AB^(2)=4AD^(2)( b) 3AB^(2)=4AD^(2)(c)4AB^(2)=3AD^(2)(d)2AB^(2)=3AD^(2)

If AD, BE and CF are the medians of a ABC ,then (AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2)) is equal to

In Delta ABC , AD is a median and AM _|_ BC.Prove that (a) AC^(2) = AD^(2) +BC.DM+ ((BC)/(2))^(2) (b) AB^(2) = AD^(2) -BC.DM+ ((BC)/(2))^(2) (c ) AC^(2) + AB^(2) = 2AD^(2) +(1)/(2) BC^(2)