Each rod of a centrifugal governor is 10 cm long then the number of revolutions per second made when the rod include at an angle of `60^(@)` will be `(g=9.8 m//s^(2))`

Each rod of a centrifugal governor is 10 cm long. Then the number of revolutions persecond made when the rod inclined at an angle of 60^@ will be

If a speed man is rotated at the end of a long beam of length 5m and the acceleration of 9g, then the number of revolution performed will be ( g=10 m//s^(2))

A metal rod 1/ (sqrt(pi)) meter long rotates about one of its ends perpendicular to a plane whose magnetic induction is 4xx10^-3T . Calculate the number of revolutions made by the rod per second if the e.m.f. induced between the ends of the rod is 16mV.

The breaking stress of a cylindrical rod is 10^(6) N//m^(2) . If the maximum possible height of the rod is 10 m, then the density of the material of the rod is [use g = 10m//s^(2) ]

A rod AB is shown in figure. End A of the rod is fixed on ground. Block is moving with velocity sqrt3 m/s towards right. The velocity of end B of rod when rod makes an angle of 60^@ with ground is :

A rod AB is shown in figure. End A of the rod is fixed on ground. Block is moving with velocity m/s towards right. The velocity of end B of rod when rod makes an angle of 60^@ with ground is :