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inte^(sinx)(xcosx-secxtanx)dx...

`inte^(sinx)(xcosx-secxtanx)dx`

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Evaluate: inte^(xsinx)[xcosx+sinx]dx

int(xsinx)/(xcosx-sinx-1)dx="_______"+c

int(xsinx)/(xcosx-sinx-1)dx="_______"+c

int(xsinx)/(xcosx-sinx-1)dx= . . . . . +c .

intx^2/(xcosx-sinx)^2dx

inte^(sinx)((sinx+1)/(secx))dx

int(sinx*cosx)dx

inte^(sinx)((sinx+1)/(secx))dx is equal to

int(sinx)/(sinx-cosx)dx=

int(sinx)/(sinx-cosx)dx=