Let `E = [1/3 + 1/50] + [1/3 + 2/50] + . . . +` upto 50 terms, then exponent of 2 in `(E)!` is

Statement 1: Let E=[1/3+1/(50)]+[1/3+2/(50)]+ upto 50 terms, then E is divisible by exactly two primes. Statement 2: [x+n]=[x]+n ,n in I and [x+y]=[x]+[y] if x ,y in I

Statement 1: Let E=[1/3+1/(50)]+[1/3+2/(50)]+ upto 50 terms, then E is divisible by exactly two primes. Statement 2: [x+n]=[x]+n ,n in I and [x+y]=[x]+[y] if x ,y in I

Let E = [(1)/(3) + (1)/(50)]+[(1)/(3)+(2)/(50)]+[(1)/(3)+(3)/(50)]+…….. upto 50 terms where [.] denotes the greatest integer terms then

Let E = [(1)/(3) + (1)/(50)]+[(1)/(3)+(2)/(50)]+[(1)/(3)+(3)/(50)]+…….. upto 50 terms where [.] denotes the greatest integer terms then

Statement 1: Number of zeros at the end of 50 ! is equal to 12. Statement 2: Exponent of 2 in 50! is 47.

Statement 1: Number of zeros at the end of 50! is equal to 12. Statement 2: Exponent of 2 in 50! is 47.

Statement 1: Number of zeros at the end of 50! is equal to 12. Statement 2: Exponent of 2 in 50! is 47.

1,-1,1,-1,….upto 100 terms then what is 50^(th) term?

Let p be prime number such that 3 < p < 50 , then p^2 - 1 is :

"Let "f(x)=x + (1)/(2x + (1)/(2x + (1)/(2x + .....oo))). Then the value of f(50)cdot f'(50) is -