A space ship is fired from the earth's surface with an intial speed of `2xx10^(4)m//s.` Its speed when it is far from the earth is
`(g=9.8m//s^(2),R=6.4xx10^(6)m)`

The critical speed of a satellite orbiting very close to the surface of the earth is [g=10 m//s^(2) and R=6.4xx10^(-6)m]

A body is released at a distance far away from the surface of the earth. Calculate its speed when it is near the surface of earth. Given g=9.8ms^(-2) radius of earth R=6.37xx10^(6)m

A body is released at a distance far away from the surface of the earth. Calculate its speed when it is near the surface of earth. Given g=9.8ms^(-2) radius of earth R=6.37xx10^(6)m

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and g = 9.8 m//s^(2)

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .

Aparticle is projected from the surface of the earth with an intial speed of 4.0 km//s .Find the maximum height attained by the particle. Radius of earth = 6400km g = 9.8 m//s^(2) .

A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km above the earth's surface. What is the (i) orbital speed and (ii) period of revolution of the satellite ? Radius of the earth, R=6.38xx10^(6) m, and acceleration due to gravity on the surface of the earth, g=9.8 ms^(-2) .

At what altitude , the acceleration due to gravity reduces to half of its value as that on the surface of the earth ? Take radius of earth as 6 . 4 xx 10^(6) m , g on the surface of the earth as 9.8 m//s ^(2) .