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Find the following sum: 1/(n !)+1/(2!(n-...

Find the following sum: `1/(n !)+1/(2!(n-2)!)+1/(4!(n-4)!)+. . . .`

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Let S_n = 1 (n - 1) + 2. (n -2) + 3. (n - 3) +…+ (n -1).1, n ge 4. The sum sum_(n = 4)^oo ((2S_n)/(n!) - 1/((n - 2)!)) is equal to :