`If alpha,beta,gamma "are in A.P. show that" cot beta = (sin alpha - sin gamma)/(cos gamma -cos alpha)`

If alpha , beta , gamma in [0,pi] and if alpha , beta , gamma are in A.P then ( sin alpha - sin gamma)/( cos gamma -cos alpha) is equal to

If alpha, beta, gamma in [0, pi]"and if" alpha, beta, gamma are in AP, then (sin alpha - sin gamma)/(cos gamma - cos alpha) is equal to

If alpha+gamma=2beta then the expression (sin alpha-sin gamma)/(cos gamma-cos alpha) simplifies to:

If alpha+gamma=2beta then the expression (sin alpha-sin gamma)/(cos gamma-cos alpha) simplifies to:

If alpha, beta, gamma ,are positive acute angles and sin (alpha+beta-gamma)=cos(beta+gamma-alpha)=tan (gamma+alpha-beta)=1 find alpha,beta and gamma .

If cos alpha + cos beta + cos gamma = sin alpha + sin beta + sin gamma = 0 , show that cos 3alpha + cos 3 beta + cos gamma = 3 cos (alpha + beta + gamma) and

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then show that cos 3 alpha + cos 3 beta + cos 3 gamma = 3 cos ( alpha + beta + gamma)

If sin alpha,sin beta,sin gamma are in AP then cos alpha,cos beta,cos gamma are in GP then (cos^(2)alpha+cos^(2)gamma-4cos alpha cos gamma)/(1-sin alpha sin gamma)=

If cos alpha + cos beta + cos gamma = 0 = sin alpha + sin beta + sin gamma then show that cos ( alpha + beta) + cos ( beta + gamma) + cos ( gamma + alpha) = 0

If cos (beta - gamma) + cos (gamma - alpha) + cos (alpha - beta) = -3/2, "show that", cos alpha + cos beta + cos gamma = 0 "and" sin alpha + sin beta + singamma = 0."Hence deduce that," cos (beta - gamma) = cos (gamma - alpha) = cos (alpha - beta) = -1/2.